Example : Conversion: 100 ppmNO3−in mol/L
Given : 100 ppmNO3−= 100 mg/L
1. Molar mass ofNO3−
- Nitrogen (N): 14.01 g/mol
- Oxygen (O): 3 × 16.00 = 48.00 g/mol
- Total: 62.01 g/mol
2. Conversion to mol/L
Calculation:
Result
100 ppmNO3−≈ 1.61 mmol/L
Sources
- Petrucci, Harwood, Herring, Madura – General Chemistry: Principles and Modern Applications , 10th Edition
- PubChem – Nitrates (NO₃⁻)
Example: 2 ppmFe3in mol/L
Given: 2 ppm = 2 mg/L iron(III)
1. Molar mass ofFe3
- Fe (iron): 55.85 g/mol
2. Conversion to mol/L
Calculation:
c=2 mg55.85 g/mol=0.002 g/L55.85 g/mol≈0.0358 mmol/L = 35.81 μmol/L = 3.5810e-5 mol/L
Result
2 ppmFe3≈ 35.8 µmol/L
Sources
- Atkins, P. & Jones, L. – Chemistry: Molecular Nature of Matter and Change , 6th Edition
- PubChem – Iron (Fe)
PPM conversion – formula overview
Definition: 1 PPM = 1 mg per liter of water
PPM → mg:
mg = PPM × Volumen (in L)
mg → g:
g = mg ÷ 1000
g → kg:
kg = g ÷ 1000
mg → mL (for stock solution):
mL = mg ÷ Konzentration (mg/mL)
Example: Stock solution contains 100 g/L → 100 000 mg / 1000 mL = 100 mg/mL
PPM → mL stock solution:
mL = (PPM × Volumen (L)) ÷ Konzentration (mg/mL)
Note: For more accurate conversions, consider the density of concentrated solutions or other liquids!
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